rean_jem Posted February 7, 2009 Share Posted February 7, 2009 when getting a return pump, do i include the volume of the sump when calculating for turnover in the display? Link to comment
121a Posted February 7, 2009 Share Posted February 7, 2009 no, the sump should only have the turnover the pump provides, say a 300gph pump, you will have 300gph turnover. The display tank has circulating pumps, meaning they just move the water inside the tank, the only water that will be flowing down the drain will be the return pump water. Is this what you asked? Link to comment
rean_jem Posted February 7, 2009 Author Share Posted February 7, 2009 its a little confusing, i know lol, but to make it clearer. i have a 8.5gal display with a 10 gal sump and would like to get a 317gph eheim pump. the total head would be like 3ft. i figured the output will be more or less 150gph at the display. so when i calculate the turnover is it 150/8.5 or 150/(8.5+10)? thanks btw it will be my main flow in the tank. Link to comment
121a Posted February 7, 2009 Share Posted February 7, 2009 150/8.5, no need to add the sump volume as it will be the same as the display with return pump only. But IMO you need a bit more flow in the display, something like a korlia nano would do the trick. Link to comment
rean_jem Posted February 7, 2009 Author Share Posted February 7, 2009 17x turnover in the display you think is not enough? i thought 10x turnover min is good? Link to comment
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