A bit of a n00b question that I'm embarrassed to ask, but I didn't find an answer in any build threads.
The label on my Meanwell LPC-35-700 says it outputs 48V. If I use it to drive fewer than 12 or 13 LEDs, I won't need a resistor to drop the voltage, will I? It's not going to overvolt the LEDs w/o one?
The data sheet says the output is actually 9V - 48V. I'm guessing that this means it's perfectly safe to drive 8 LEDs w/o needing resistors. Just thought I'd ask first.
Full Version: Meanwell Driver output question
i think there is a voltage knob inside but i could be mistaken
QUOTE (cparka23 @ Mar 18 2010, 01:20 PM) 
A bit of a n00b question that I'm embarrassed to ask, but I didn't find an answer in any build threads.
The label on my Meanwell LPC-35-700 says it outputs 48V. If I use it to drive fewer than 12 or 13 LEDs, I won't need a resistor to drop the voltage, will I? It's not going to overvolt the LEDs w/o one?
The data sheet says the output is actually 9V - 48V. I'm guessing that this means it's perfectly safe to drive 8 LEDs w/o needing resistors. Just thought I'd ask first.
The label on my Meanwell LPC-35-700 says it outputs 48V. If I use it to drive fewer than 12 or 13 LEDs, I won't need a resistor to drop the voltage, will I? It's not going to overvolt the LEDs w/o one?
The data sheet says the output is actually 9V - 48V. I'm guessing that this means it's perfectly safe to drive 8 LEDs w/o needing resistors. Just thought I'd ask first.
LPCs are constant current mode drivers, and as long as the combined voltage drop of the connected LEDs is within the operating voltage (9-48v), the driver will adjust automatically.
Thank you, LED Guru! Looking forward to getting this one done and hung over the tank. It's been more fun than I anticipated, so I just might do another one! 
That's the spirit 
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